I got a new IOT device and it came with a BL602 on a breakout board. I am not sure what the layout of this board is and how I would connect to get it flashed. If anyone can provide me with some tips that would be great.
BT = BooT = Bootloader.
RX from board should be connected to TX from UART to USB converter, and TX from board should be connected to RX from USB to UART converter.
(UNLESS someone is using non-standard naming on board, then please switch RX and TX).
Are you aware that you should use 3.3V power supply for that? 5V connected to 3.3V pin would burn BL602.
What i meant was which pin corresponds to which pin on the board.
so 3v3 pin is obvious the 3 volt pin
Gnd is obviously ground
but then its only written as 22 17 C W
maybe if you could specify
22 = ?
17 = ?
C = ?
and im not sure if we need the pins on the back of the board.
Well that is the issue. Figuring out the pinout from the chip diagram to the actual board.
So we know we need for example TX and RX and the BOOT pin but which pins are those on the actual PCB board that are labeled using that combination of letters.
I am really not good at following the traces on the board. I suspect that these letters and numbers mean something but i'm not experience enough either to know what they are referring too.
I cant post a link to the product but its just a lamp holder. Its a socket for a light bulb nothing else. It should just turn a bulb on or off.